a-[2a-[b-(3a-2b)]]=0

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Solution for a-[2a-[b-(3a-2b)]]=0 equation:


Simplifying
a + -1[2a + -1[b + -1(3a + -2b)]] = 0
a + -1[2a + -1[b + (3a * -1 + -2b * -1)]] = 0
a + -1[2a + -1[b + (-3a + 2b)]] = 0

Reorder the terms:
a + -1[2a + -1[-3a + b + 2b]] = 0

Combine like terms: b + 2b = 3b
a + -1[2a + -1[-3a + 3b]] = 0
a + -1[2a + [-3a * -1 + 3b * -1]] = 0
a + -1[2a + [3a + -3b]] = 0

Combine like terms: 2a + 3a = 5a
a + -1[5a + -3b] = 0
a + [5a * -1 + -3b * -1] = 0
a + [-5a + 3b] = 0

Combine like terms: a + -5a = -4a
-4a + 3b = 0

Solving
-4a + 3b = 0

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-3b' to each side of the equation.
-4a + 3b + -3b = 0 + -3b

Combine like terms: 3b + -3b = 0
-4a + 0 = 0 + -3b
-4a = 0 + -3b
Remove the zero:
-4a = -3b

Divide each side by '-4'.
a = 0.75b

Simplifying
a = 0.75b

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